Question

Given that the specific heat of chromium is 0.455J/g∙K find the final temperature after 35.9J of energy is removed from 11.7g of chromium at 28.5°C.

Answer 1

`T_2=35.2\°C`

Step-by-step explanation:

Hello,

In this case, since the heat is computed in terms of mass, specific heat and temperature as follows:

`Q=mCp(T_2-T_1)`

In such a way, for the given heat, we obtain the following temperature:

`T_2=T_1+(Q)/(mCp)\\ \\T_2=28.5\°C+(35.9J)/(11.7g*0.455(J)/(g\°C) )\\ \\T_2=35.2\°C`

Best regards.