Explanation:
Let the distance points E(3,7) and F(6,5)
Distance between EF = √[(x2-x1)²+(y2-y1)²]→Formula
Here, x1 = 3, y1 = 7
x2 = 6 , y2 = 5
Now,
Put all the values in distance formulae:
AB = √[(6-3)²+(5-7)²]
= √[(4)²+(2)²]
= √[(4*4)+(2*2)]
= √[16+4]
= √[20] = 2√5 Units.
Answer:- Hence, the distance between two points E(3,7) and F(6,5) is 2√5 Units.