Answer & Step-by-step explanation:
Assuming that there is a constant rate of change, we can use the equation:
![y=kx](https://img.qammunity.org/2021/formulas/mathematics/middle-school/15ggalazf8cpjag5fv34y8ftpnv14l6oxo.png)
k is the constant rate of change. Set up an equation in which the pounds are determined by the rate of change between kilograms and pounds:
![1=k(2.2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/v5g3717gzbsfwfeqsdq6qrwqommvh9vd0o.png)
Isolate the variable k:
![(1)/(2.2)=(k(2.2))/(2.2)\\\\(1)/(2.2)=k](https://img.qammunity.org/2021/formulas/mathematics/high-school/o2tbeh3mxrkili8fziat9s3p3ppexq6r2w.png)
Set up another equation like so:
![(y)/(x)=(y)/(x)](https://img.qammunity.org/2021/formulas/mathematics/high-school/cf2szxczah1720c5m27knjcjjddj9l11yw.png)
Insert values:
![(1)/(2.2)=(y)/(112)](https://img.qammunity.org/2021/formulas/mathematics/high-school/xm0uibggcij05feeasdogepjgry99f8qxo.png)
Solve for y. Cross multiply:
![1(112)=2.2y\\\\112=2.2y](https://img.qammunity.org/2021/formulas/mathematics/high-school/qbj8llu9torjqk1mez4lxdscikhvbok3hm.png)
Isolate the variable. Divide both sides by 2.2:
![(112)/(2.2)=(2.2y)/(2.2) \\\\ y=50.9090...](https://img.qammunity.org/2021/formulas/mathematics/high-school/585524oivcapqo9mlkxcc0vbouxvffudr8.png)
So, there are about 50.9 kilograms in 112 pounds.
:Done