Question

9. How many grams of zinc are needed to produce 12 grams of zinc chloride according to the following equation? Y-

Zn + Cl2 --> ZnCl2
12 grams of zinc
O 2.9 grams of zinc
O 11.6 grams of zinc
O 5.8 grams of zinc

Answer 1

Given :

A balanced chemical equation :

`Zn +Cl_2->ZnCl_2`

To Find :

How many grams of zinc are needed to produce 12 grams of zinc chloride.

Solution :

Moles of
`ZnCl_2` ,

`n=(Given \ wt)/(Molecular\ Mass)\\\\n =(12)/(136.30)\ mol\\\\n=0.088\ mol`

Now, by balanced chemical equation we can say that 1 mol of Zn produce

1 mol of
`ZnCl_2` .

So, 0.088 mol of Zn is required to produced 0.088 mol of
`ZnCl_2` .

`Mass \ required = molecular \ mass * moles\\\\m = 65.38 * 0.088\\\\m=5.8 \ gm`

Therefore, 5.8 grams of zinc is required.

Hence, this is the required solution.