Question

A skater slides across the ice with an initial velocity of 5.0 m/s. She slows 10 points

to a velocity of 2 m/s over a distance of 20 m. What is her initial velocity?

Answer 1

Step-by-step explanation:

Given that,

The initial velocity of a skater is, u = 5 m/s

She slows to a velocity of 2 m/s over a distance of 20 m.

We can find the acceleration of skater. It is equal to the rate of change of velocity. So, it can be calculated using third equation of motion as follows :

`v^2-u^2=2as`

a = acceleration

`a=(v^2-u^2)/(2s)\\\\a=((2)^2-(5)^2)/(2* 20)\\\\a=-0.525\ m/s^2`

So, her acceleration is
`0.525\ m/s^2` and she is deaccelerating. Also, her initial velocity is given i.e. 5 m/s.