Question

Find the number of CoCl2 units present in a 0.78 mol sample.

Answer 1

`\qquad\qquad\huge\underline{{\sf Answer}}`

Here we go ~

1 mole of
`\sf{ COCl_2}` has 6.022 × 10²³ molecules of the given compound.

So, 0.78 mole of
`\sf{COCl_2}` will have ~

`\qquad \sf  \dashrightarrow \: 0.78 * 6.022 * 10 {}^(23)`

`\qquad \sf  \dashrightarrow \: \approx4.7 * 10 {}^(23) \: \: \: molecules`