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if α,β are the roots of the equation x^{2}-3x+2=0 form an equation whose roots are (α+β)² & (α-β)²

User Bpapa
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1 Answer

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Solution:-

Let's find roots of x² - 3x + 2

=> x² - 3x + 2 = 0.

=> x² - x - 2x + 2 = 0.

=> x ( x - 1 ) -2 ( x - 1) = 0.

=> ( x - 1 ) ( x - 2 ) = 0.

=> x = 2, 1.

Now

  • ( a + ß )² = (2+1)²=3²=9
  • ( a - ß )² = ( 2 - 1 )² = 1² = 1.

So , equⁿ would be ,

=> x² - ( 9 + 1)x + 9×1=0.

=> x² - 10x + 9=0.

User Sole
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