Solution:-
Let's find roots of x² - 3x + 2
=> x² - 3x + 2 = 0.
=> x² - x - 2x + 2 = 0.
=> x ( x - 1 ) -2 ( x - 1) = 0.
=> ( x - 1 ) ( x - 2 ) = 0.
=> x = 2, 1.
Now
- ( a + ß )² = (2+1)²=3²=9
- ( a - ß )² = ( 2 - 1 )² = 1² = 1.
So , equⁿ would be ,
=> x² - ( 9 + 1)x + 9×1=0.
=> x² - 10x + 9=0.