Question

Write the equation of a line that is parallel to 4x-2y=3 and is passing through the point (2,1)

Answer 1

y= 2x -3

Explanation:

Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.

4x -2y= 3

2y= 4x -3

Divide by 2 throughout:

`y = 2x - 1 (1)/(2)`

Thus the gradient is 2.

Parallel lines have the same gradient thus the line would also have a gradient of 2.

Substitute m=2 into the equation:

y= 2x +c

To find the value of c, substitute a pair of coordinates.

When x=2, y=1,

1= 2(2) +c

1= 4 +c

c= 1 -4

c= -3

Thus, the equation of the line is y= 2x -3.