Answer:
-338
Explanation:
So we have the sequence:
5, -2, -9, -16...
First, note that this is an arithmetic sequence.
This is because each individual term is the previous term added by a common difference.
We can see that this common difference is -7, because each subsequent term is 7 less than the previous one. For example, 5 minus 7 is -2, -2 minus 7 is -9, and so on.
So, to find the 50th term, we can write an explicit formula for our sequence.
The standard form for the explicit formula for an arithmetic sequence is:
![x_n=a+d(n-1)](https://img.qammunity.org/2021/formulas/mathematics/college/9v9nh0v9618bue1r1pzkbw348rxpoxmn8f.png)
Where a is the initial term, d is the common difference, and n is the nth term.
We can see that our initial term a is 5. And we also already determined that the common difference d is -7. So, substitute:
![x_n=5-7(n-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/610qpgceossdlulpsaf4knkqrynfdiho3w.png)
Now, to find the 50th term, all we have to do is to substitute 50 for n. So:
![x_(50)=5-7(50-1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/br56paxntg7kubdcrey2snw31uw36dprqj.png)
Subtract within the parentheses:
![x_(50)=5-7(49)](https://img.qammunity.org/2021/formulas/mathematics/high-school/dxjge5i0varhb5ffv0gzilbd0sks2e1lfc.png)
Multiply:
![x_(50)=5-343](https://img.qammunity.org/2021/formulas/mathematics/high-school/rv6htimp0kqsqi7l0uiz1a6vz5qupglt0b.png)
Subtract:
![x_(50)=-338](https://img.qammunity.org/2021/formulas/mathematics/high-school/fs9ha2h9aqz150l7ya6g3zyz2cduktidmq.png)
So, the 50th term is -338.
And we're done!