Final answer:
The correct mole to mole ratio for Aluminum to Aluminum chloride in the reaction 2Al + 3Cl2 -> 2AlCl3 is 1:1.
Step-by-step explanation:
The correct mole to mole ratio for Aluminum to Aluminum chloride in the reaction 2Al + 3Cl2 → 2AlCl3 is 1 : 1. Each mole of Aluminum reacts to form one mole of Aluminum chloride, as indicated by the coefficients in the balanced chemical equation. Using stoichiometry and the given balanced equation, we can determine that if 2.0 moles of Aluminum reacts completely, it will produce 2.0 moles of Aluminum chloride if chlorine gas is not limiting.