Answer:
Explanation:
Let the probability of people being white be P ( W ) and being diseased
be P ( D )
Given
P ( W ) = .72 , P ( D ) = .3
P ( W∩D ) = .2
a )
P (
∩
) = P
= 1 - P ( W U D )
= 1 - [ P( W ) + P ( D ) - P ( W ∩ D ) ]
= 1 - ( .72 + .3 - .2 ) = .18
b )
P ( D / W ) = P ( W∩D ) / P(W) = .2 / .72 = .27778
c )
No , because
P ( W∩D ) = .2
p ( W) x P ( D ) = .72 x .3 = .216
so P ( W∩D ) is not equal to P ( W) x P ( D )
d )
We shall apply binomial distribution
chance = 10C₂ x .3² ( 1 - . 3 )⁸