Question

Calculate the net force that thymine exerts on adenine. To keep the calculations fairly simple, yet reasonable, consider only the forces due to the O−H−N O − H − N and the N−H−N N − H − N combinations, assuming that these two combinations are parallel to each other. Remember, however, that in the O−H−N O − H − N set, the O− O − exerts a force on both the H+ H + and the N− N − , and likewise along the N−H−N N − H − N set.

Answer 1

hello your question is incomplete and lacks the required figure below is the missing part

The two sides of the DNA double helix are connected by pairs of bases (adenine, thymine, cytosine, and guanine). Because of the geometric shape of these molecules, adenine bonds with thymine and cytosine bonds with guanine shows the thymine adenine bond. Each charge shown is ±e, and the H−N distance is 0.110 nm

answer : net force due to O-H-N combination = -5.03354 * 10^-9 N

net force due to N-H-N combination = -3.822 * 10^-9 N

net force that the thymine exerts on adenine = -8.8558 * 10^-9 N

Step-by-step explanation:

considering only the forces due to O-H-N and N-H-N to determine the net force been exerted on adenine by thymine

we have to make some assumptions

we have to assume force towards thymine to be negative

Net force that thymine exerts on Adenine

= net force due to 0-H-N + net force due to N-H-N

= ( -5.03354 * 10^-9 ) + ( - 3.822 * 10 ^-9 )

= -8.8558 * 10 ^-9 N

ATTACHED BELOW IS THE REMAINING PART OF THE SOLUTION