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What pressure, in atm, is required to reduce 60.0 mL of a gas at standard conditions to 10.0 mL at a temperature of 25.0 °C?
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22 votes
22 votes
What pressure, in atm, is required to reduce 60.0 mL of a gas at standard conditions to

10.0 mL at a temperature of 25.0 °C?

User Gaurav Thakur
by
3.0k points

1 Answer

14 votes
14 votes
P1=1atm
V1=60mL
V2=10mL
P2=?
P2=P1*V1/V2
=1*60/10
=6 atm#
User Amirhosseinab
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3.5k points
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