Question

Lexy throws a dart with an initial velocity of 25 m/s at an angle of 60° relative to the ground. What is the approximate vertical component of the initial velocity?

0.5 m/s
0.87 m/s
12.5 m/s
21.7 m/s

Answer 1

I took the test and got 21.7 m/s correct i am glad to help anytime.

Answer 2

Option D: 21.7 m/s

Step-by-step explanation:

We are given;

Initial velocity; u = 25 m/s

Launch Angle; θ = 60°

In projectile motion, the component of velocity vertically and horizontally are;

Vertical component; v = u sin θ

Horizontal component; v = u cos θ

Now, we want to find the approximate vertical component of the initial velocity.

Thus;

v = u sin θ

v = 25 sin 60

v = 25 × 0.866

v = 21.65 m/s ≈ 21.7 m/s