Question

A group of 6 hikers are preparing for a one week trip. All of the group's supplies will be carried by the hikers in

backpacks. The leader decides that each hiker will carry a backpack that is the same fraction of weight to all the other
hikers' weights. This means that the heaviest hiker would carry the heaviest load. The table below shows the weight of
each hiker and the weight of the backpack
Complete the table. Find the missing, amounts of weighit by applying the same value of the ratio as the first two rows.
Backpack Weight
Hiker's Weight
152 15.402
Total Weight (lb.)
14 1b, 802
107 lb, 10 oz
10 lb. 4 02
129 lb. 15 02
68 10.40
8 lb. 12 oz
10 lb

Answer 1

Explanation:

1 oz = 0.0625 lb

Ratio of the hiker an backpack in the first row = 152.25 lb : 14.5 lb

= 21 : 2

Hiker's weight Backpack weight Total weight (in lb)

1). 152 lb 4 oz 14 lb 8 oz (152+14) lb (4+8) oz = 164lb 12oz

= 16.75 lb

2). 107 lb 10 oz 10 lb 4 oz (107+10) lb (10+4) oz = 117 lb 14 oz

= 117.875 lb

3). 129 lb 15 oz
`(129.9375)/(x)=(21)/(2)` (129+12) lb (15+6)oz = 141 lb 21 oz

x = 12.375 lb = 142.3125lb

x = 12 lb 6 oz

4).
`(x)/(8.75)=(21)/(2)` 8 lb 12 oz (8 + 91) lb (14+12) oz = 99 lb 26 lb

x = 91.875 lb = 100.625 lb

x = 91 lb 14 oz

5).
`(x)/(10)=(21)/(2)` 10 lb (105 + 10) lb = 115 lb

x = 105 lb