Answer:
The liver cell with ∆G'° = -2.34 kJ/mol
Note: The question is incomplete. The complete question is given below:
The following data represents cellular concentrations of ATP, ADP, and inorganic phosphate from various mammalian organs. Calculate the actual Gibbs free energy change for hydrolysis of ATP under physiological conditions (assume 37°C). Assume ATP hydrolysis has a standard free energy change of -30.5 kJ/mol. Which cell type yields the greatest free energy change for ATP hydrolysis? Show your work. ATP (MM) ADP (mm) Pi. (mm) Liver 3.5 1.8 5.0 Muscle 8.0 0.9 8.0 Brain 2.6 0.7 2.7 mM=millimolar, ATP=adenosine triphosphate, ADP-adenosine diphosphate, Pi=inorganic phosphate
Step-by-step explanation:
The equation for ATP hydrolysis is as follows: ATP ---> ADP + Pi
Standard free energy change, ∆G'° = -RTlnK'eq;
where K'eq is equilibrium constant; R = 8.315 J/mol.K; T = 298 K
K'eq = {[ADP][Pi]}/[ATP]
For Liver:
∆G'° = -(8.315)(298) × ln (1.8 × 5.0/3.5)
∆G'° = -2.34 kJ/mol
For Muscle
∆G'° = -(8.315)(298) × ln (0.9 × 8.0/8.0)
∆G'° = 0.261 kJ/mol
For Brain
∆G'° = -(8.315)(298) × ln (0.7 × 2.7/2.6)
∆G'° = 0.79 kJ/mol