Question

If the temperature outside was 73 degrees at 5:00 p.m. but if fell 19 degrees by 10 p.m. What is the temperature at 10:00 p.m.? Write an equation and solve.

Answer 1

54°

Explanation:

1. 73° at 5pm - dropped 19 by 10 pm

2. subtract using this equation: 73 - 19 =

3. solve- 73 - 19 = 54

hope this helps!!!