Question

To practice Problem-Solving Strategy 2.1 Motion with constant acceleration You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 10 m/s2 . How much distance is between you and the deer when you come to a stop?

Answer 1

5 m

Step-by-step explanation:

First, we need to find the distance traveled by car in the 0.50 s:

`x = v*t = 20 m/s*0.5 s = 10 m`

Now, we can find the distance traveled by car when the brakes are applied:

`V_(f)^(2) = V_(0)^(2) - 2ax`

`x = (V_(0)^(2))/(2a) = ((20 m/s)^(2))/(2*10 m/s^(2)) = 20 m`

Finally, the distance between the car and the deer is:

`d = 35 m - 10 m - 20 m = 5 m`

Therefore, the distance between the car and the deer is 5 m.

I hope it helps you!