Answer:
26 yards
Explanation:
The complete question is attached in the image below.
The distance between two points O(
) and P(
) is:
![|OP|=√((x_2-x_1)^2+(y_2-y_1)^2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8wyj3ibyuoleezgdw93chche24wv8nwk8o.png)
The location of the points of the polygon are as follows:
A(-5, 5), B(0. 5), C(4,2), D(1, -2), E(-2, -2), F(-5, 2). Therefore:
![|AB|=√((0-(-5))^2+(5-5)^2)=5\ yards \\\\|BC|=√((4-0)^2+(2-5)^2)=5\ yards \\\\|CD|=√((1-4)^2+(-2-2)^2)=5\ yards \\\\|DE|=√((-2-1)^2+(-2-(-2))^2)=3\ yards\\ \\|EF|=√((-5-(-2))^2+(2-(-2))^2)=5\ yards \\\\|FA|=√((-5-(-5))^2+(2-5)^2)=3\ yards](https://img.qammunity.org/2021/formulas/geography/college/lvqalntv1h4417ipvzxmh8si56phwxuwwv.png)
The perimeter of the fence = |AB| + |BC| + |CD| + |DE| + |EF| + |FA| = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards.