Question

12) A 26 kg chunk of ice is slid west across the frictionless surface of a frozen lake at 1.7 m/s . The chunk of ice collides with another chunk of ice, which is stationary and has a mass of 12 kg. The two chunks slide together as a single piece after the collision Calculate the final velocity of the combined ice chunks Show your work including the equation(s), values for the variables, and units

Answer 1

1.16 m/s

Step-by-step explanation:

Mass of first ice; m1 = 26 kg

Mass of second ice; m2 = 12 kg

Velocity of first ice; v1 = 1.7 m/s

Velocity of second ice; v2 = 0 m/s

From inelastic collision, the formula we will use is;

m1•v1 + m2•v2 = (m1 + m2)v'

Where v' is the final velocity of the combined ice chunks

Plugging in the relevant values gives;

(26 × 1.7) + (12 × 0) = (26 + 12)v'

44.2 = 38v'

v' = 44.2/38

v' ≈ 1.16 m/s