Answer:
The answer is "
"
Explanation:
In this question, we calculates the roots value after compare with 0.
In the first point:
![\to \bold{x^2 - 2x - 8 < 0}](https://img.qammunity.org/2021/formulas/mathematics/high-school/efrayhx1wdqcmli0gwihh0icp35om55lpp.png)
![x^2 - (4-2)x - 8 < 0\\\\x^2 - 4x +2x - 8 < 0\\\\x(x - 4) +2(x - 4) < 0\\\\ \ \ \ (x - 4)(x + 2) < 0](https://img.qammunity.org/2021/formulas/mathematics/high-school/efoyafwe9mqzbaxlytn9pubt72a2avtuq9.png)
In the second point:
![\to \bold{x^2 + 2x - 8 < 0}](https://img.qammunity.org/2021/formulas/mathematics/high-school/tgsstxbbhukl8axk0lrifc3wllp26a2em9.png)
![x^2 + (4-2)x - 8 < 0\\\\x^2 +4x -2x - 8 < 0\\\\x(x + 4) -2(x +4) < 0\\\\ \ \ \ (x + 4)(x - 2) < 0\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/opnkjpb11e0iolihb2hz8iq905t35hnvkh.png)
In the third point:
![\to \bold{x^2 - 2x - 8 > 0}](https://img.qammunity.org/2021/formulas/mathematics/high-school/otlioya4v04m1bet122kt5qbmnfx25b2ba.png)
![x^2 -(4-2)x - 8 < 0\\\\x^2 -4x +2x - 8 < 0\\\\x(x - 4) +2(x -4) < 0\\\\ \ \ \ (x - 4)(x + 2) < 0\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/8uy1s6g1obttasuu3427qx65x2a48v9k07.png)
In the fourth point:
![\to \bold {x^2 + 2x - 8 > 0}](https://img.qammunity.org/2021/formulas/mathematics/high-school/har05te7fwolyryid6nhly73f5q909kfkl.png)
![x^2 +(4-2)x - 8 < 0\\\\x^2 +4x -2x - 8 < 0\\\\x(x + 4) -2(x +4) < 0\\\\ \ \ \ (x + 4)(x - 2) < 0\\](https://img.qammunity.org/2021/formulas/mathematics/high-school/c8q9wousiij5doxhqkw9d4vtuyfx7ugjdv.png)
As there are roots -4 and 2, whether choice B and D is the answer. when measuring a point within the interval from -4 to 2, it is negative, that's why second choice is correct.