Question

Please help me answer this question...

Answer 1

`\begin{gathered} \begin{array} \pmb{ \sf{Electrolyte}}& \textsf{ \textbf{Formula of Ions}}\\ \\ \\ \sf sodium \: sulphate& \bf \red{Na_2SO_4} \\ \\ \sf magnesium \: chloride& \red{ \bf MgCl_2} \\ \\ \sf zinc \: sulphate & \bf \red{ZnSO_4} \\ \\ \sf potassium \: iodine& \red{ \bf KI} \\ \\ \sf sodium \: hydroxide& \bf \red{NaOH} \\ \\ \sf Copper(II) \: chloride & \red{ \bf CuCl_2} \\ \\ \sf silver \: nitrate& \red{ \bf{AgNO_3}}\end{array}\end{gathered}`

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• Sodium sulphate

valency:

Sodium -
`\sf Na^+`

sulphate -
`\sf {SO_4}^(-2)`

• Magnesium Chloride

valency:

Magnesium-
`\sf Mg^(+2)`

Chloride-
`\sf Cl^(-1)`

• zinc sulphate

valency:

zinc-
`\sf Zn^(+2)`

sulphate
`\sf SO_4^(-2)`

• potassium iodine

valency:

potassium -
`\sf K^(+1)`

sulphate -
`\sf I^(-1)`

• sodium hydroxide

valency:

sodium -
`\sf Na^(+1)`

hydroxide -
`\sf OH^(-1)`

• Copper(II) chloride

valency:

Copper(II) -
`\sf Cu^(+2)`

chloride -
`\sf Cl^(-1)`

• Silver nitrate

valency:

Silver -
`\sf Ag^(+1)`

nitrate -
`\sf NO_3^(-1)`

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Key Points :

• Remember metals always have positive valency because lose their electrons from their valence shell to obtain Nobel gas configuration.

• And bases always have negative valency because they gain electronics to complete their shell and hence to obtain Nobel gas configuration.

• Metals are always written before bases

• While writing formula if both Ions have same valency then we don't write them in formula.

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