Question

Charle's Law

At 225 °C a gas has a
volume of 400 mL. What is
the volume of this gas at 127
°C?

Given:

Unknown:

Formula:

Solution:

Final answer:​

Answer 1

Convert temperature to Kelvin

• 225°C=498K
• 127°C=400K

Convert vol to L

• 400mL=0.4L

Apply Charles law

• V1T_2=V2T_1
• 0.4(400)=498V_2
• 160=498V_2
• V_2=0.32L=320mL

Answer 2

Given:

`V_(1) = \text{400.0 mL}`

`T_(1) = 225.0^(\circ)\text{C + 273.15 = 498.15 K}`

`T_(2) = 127.0^(\circ)\text{C + 273.15 = 400.15 K}`

Unknown:

`V_(2)`

Solution:

`(V_(1))/(T_(1)) = (V_(2))/(T_(2))`

`V_(2) = V_(1) * (T_(2))/(T_(1))`

`V_(2) = \text{400.0 mL} * \frac{\text{400.15 K}}{\text{498.15 K}}`

`\boxed{V_(2) = \text{321.3 mL}}`

Therefore, the volume of the gas at 127.0°C is 321.3 mL

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