Question

A projectile is fired from the origin (at y = 0 m) as shown in the diagram

above. The initial velocity components are Vx = 140 m/s and Vy = 84 m/s.
The projectile reaches maximum height at point P, then it falls and strikes
the ground at point Q, which is 20 m below the launch point. Assuming air
resistance is negligible, what is the horizontal component of the velocity
(Vx) of the projectile at point P?

Answer 1

`v_(x)` =
`v_(ox)` = 140 m / s

Step-by-step explanation:

This is a projectile launch, in this case the components of the initial velocity are seen

Since there is no rice in the X axis, so the velocity is vx, it must be constant, at all times

`v_(x)` =
`v_(ox)` = 140 m / s

The vertical component of velocity changes due to having applied the gravity fiate

`v_(y)` =
`v_(oy)` - g t