Answer:
The probability is 0.2373
Explanation:
Here, we want to calculate the probability that the first 5 troubles reported on a given day were repaired on that same day.
Let P = probability that trouble reported same day is repaired = 0.75
q = probability that trouble reported is not repaired same day = 1-0.75 = 0.25
We now use the Bernoulli trial to approximate this probability of 5 being repaired same day
Mathematically, that would be;
5C5• p^5•q^0
= 5C5 * 0.75^5 * 0.25^0
= 1 * 0.2373046875 * 1
= 0.2373 approximately