The graph of f(x) = (0.2)(x^4 + x^3 – 12x^2) is shown. On a coordinate plane, a graph decreases through (4, 0) to (3, negative 11) and then curves up to (0, 0). It then curves down to (2, negative 4), - QAmmunity.org

The graph of f(x) = (0.2)(x^4 + x^3 – 12x^2) is shown. On a coordinate plane, a graph decreases through (4, 0) to (3, negative 11) and then curves up to (0, 0). It then curves down to (2, negative 4),

asked Feb 22, 2021 108k views

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