Answer: 0.754
Explanation:
Given that, it is twice as likely to come up heads as tails in a coin ;
Let tail = T ; head = H
Total possible outcomes in the coin toss = 3
Number of heads = 2
Number of tails = 1
Probability = required outcome / Total possible outcomes
Then
P(T) = 1 / 3
P(H) = 2/3
What is the most likely outcome of a series of 2000 coin tosses using this biased coin?
Most likely outcome :
P = 2/3 = 0.667 ; n = 3
Using binomial distribution formula:
nCr * p^r * (1-p)^(n-r)
P=0 :
3C0 * 0.667^0 * (1 - 0.667)^(3-0) = 0.037
P=1 :
3C1 * 0.667^1 * (1 - 0.667)^(3-1) = 0.2218 = 0.222
P= 2 :
3C2 * 0.667^2 * (1 - 0.667)^(3-2)
= 0.444
b. What is the relative probability of getting 1300 heads versus 1350 heads in a series of 2000 coin tosses using this coin?