Answer:
0.5054
Explanation:
This is a question on conditional probability.
We solve using Baye's Theorem of conditional probability
From the question
The probability of having a particular disease = 0.08.
The probability of not having a particular disease = 1 - 0.08 = 0.92
The probability of testing positive for the disease is given that a person has the disease = 0.94
The probability of testing positive given that the person does not have the disease = 0.08
Given that a person tests positive for the disease, the probability that they actually have the disease is
= (0.08 × 0.94)/(0.08 × 0.94) + (0.08 × 0.92)
= 0.0752/0.0752 + 0.0736
=0.0752/ 0.1488
= 0.5053763441
≈ Approximately to 4 decimal places = 0.5054