Answer:
X Intercepts: (2, 0), (-6, 0),
Y Intercepts: (0, – 12)
minimum: (-2,-16)
Explanation:
A) what are the x intercepts
X- axis interception points of x²+ 4x– 12:
(2,0), (-6,0)
B)what is the y intercepts
Y-axis interception point of x² + 4X – 12:
(0, – 12)
X Intercepts: (2, 0), (-6, 0), Y Intercepts: (0, – 12)
C)what is the maximum and minimum value
Parabola equation in polynomial form
The parabola params are:
a=1, b=4,c= -12
xv= -b/2a
xv= -4/2.1
simplify
xv=-2
Plug in xv = -2 to find the yv value
yv= -16
Therefore the parabola vertex is (-2, – 16)
If a<0. then the vertex is a maximum value
If a>0. then the vertex is a minimum value
a=1
minimum=(-2,-16)