Question

`log_(10)(4) - log_(10)(2 ) + log_(10)(5)`


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Answer 1

1

Explanation:

Using the rules of logarithms

logx + log y = log(xy)

logx - logy = log(
`(x)/(y)` )

`log_(b)` b = 1

Given

`log_(10)` 4 -
`log_(10)` 2 +
`log_(10)` 5

=
`log_(10)` (
`(4)/(2)` ) +
`log_(10)` 5

=
`log_(10)` 2 +
`log_(10)` 5

=
`log_(10)` (2 × 5)

=
`log_(10)` 10

= 1

Answer 2

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Hi there!

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Answer:

`= 7`

Explanation:

`(log(10))(4) - (log(10))(2) + (log(10))(5)`

`= (1)(4) - (log(10))(2) + (log(10))(5)`

`= 4 - (log(10))(2) + (log(10))(5)`

`= 4 - (1) (2) + (log(10))(5)`

`= 4 - 2(log(10))(5)`

`= 2 + (log(10))(5)`

`= 2 + (1)(5)`

`= 2 + 5`

`= 7`

❀Hope this helped you!❀

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