Question

The net fedrce on a 12 kg cart is 3.2N backward. Ignoring friction, what is the acceleration

of the car?
0.27 m/s2
3.8 m/s2
8.2 m/s2
18 m/s2
38m/s2

Answer 1

We are given with the amount of force applied and mass of a cart and we have to find the acceleration of the box.

• Force applied = 3.2 N
• Mass of the cart = 12 kg

According to Netwon's 2nd law,

After deriving, we will get that

• Force = Mass × Accleration

Plugging the given values to get mass,

➝ 3.2 N = 12 kg × accleration

➝ Accleration = 3.2 / 12 m/s²

➝ Accleration = 0.27 m/s² (approx.)

Thus, the required answer is Option A.

Carry On Learning
`!`

Answer 2

We have,

Mass,m = 12 kg

Force,F = 3.2 N

To be calculated:-

Calculate the acceleration ( a ) .

Solution:-

We know that,

`\bf \: Force = Mass × Acceleration`

`\sf\implies \: 3.2 = 12 \: * a`

`\sf \implies \: a = (3.2)/(12)`

`\sf \implies \: a = (32)/(12 * 10)`

`\sf \implies \: a \: = (8)/(3 0)`

`\sf \implies \: a = 0.266`

`\sf \implies \: a = 0.27 \: m {s}^( - 2) \: (approx)`