![\rule{300}{1}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2w6ves65xgxja0frpmrqcic9efxxwpb93y.png)
![\diamond\large\blue\textsf{\textbf{Given question:-}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/r32q2oflfss4uwm3vpx799be8uh5yywojv.png)
A cylinder has a base of 8 feet and a height of 29 ft. What is its volume
in cubic feet (ft³)?
![\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and how to solve:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/vuq5i0gsngn4dijzp8um5cx7qftrdd744x.png)
We are asked to find the volume of a cylinder, which can be found using the following formula:-
![\hookrightarrow\boxed{\bold{V=\pi r^2h}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/mqy4o73drs6wquthpqy45sjc8lj2g043vc.png)
Where:-
Provided Information:-
- r=4 ft (base = 8ft, divided by 2=4ft)
- h=29 ft
Solving for Volume:-
- Substitute 4 in lieu of r and 29 in lieu of h:-
✳︎
![\sf{V=\pi (4)^2(29)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/bcbp60ljh40hei1w2nuunvhy24hrrl8p0y.png)
On simplification,
✳︎
![\sf{V=\pi (16)(29)}](https://img.qammunity.org/2023/formulas/mathematics/high-school/v2hsshywn0t5yr7nd2lut27op2hf8te08e.png)
On further simplification,
✳︎
![\sf{V=464\pi }](https://img.qammunity.org/2023/formulas/mathematics/high-school/4pjnjb2xpso01nfhx7okmtwg2u24wkgahl.png)
Final step:-
✳︎
![\sf{V\approx1,457.7\:ft^3}](https://img.qammunity.org/2023/formulas/mathematics/high-school/439texi42ur48kferd9wu739oji2bicj3r.png)
So we conclude that the volume of the given cylinder is
![\sf{V\approx{1,457.7\:ft^3}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/z1qncurq1j24czf0pxzche1kxa7bb99t3w.png)
Good luck with your studies.
![\rule{300}{1}](https://img.qammunity.org/2023/formulas/mathematics/high-school/2w6ves65xgxja0frpmrqcic9efxxwpb93y.png)