Question

Elizabeth bought $5.00 worth of candy at the convenience store. She bought ten more 6-cent salt-water taffies than 10-cent taffies. She bought three times as many of 8-cent taffies as 10-cent taffies. She also bought two 20-cent sugar candies. How many of each kind did Elizabeth buy?

Answer 1

To find the number of each kind of candy Elizabeth bought, we can set up an equation using the given information. Solving this equation will give us the values of x and (x + 10), representing the number of 10-cent taffies and 6-cent taffies Elizabeth bought, respectively.

Step-by-step explanation:

To find the number of each kind of candy Elizabeth bought, let's assign variables to represent the unknowns.

Let's say she bought x 10-cent taffies.

Since she bought ten more 6-cent taffies than 10-cent taffies, she bought (x + 10) 6-cent taffies.

She also bought three times as many 8-cent taffies as 10-cent taffies, so she bought 3x 8-cent taffies.

Lastly, she bought two 20-cent sugar candies.

To find the number of each kind, we'll set up an equation using the information given:

• Total cost of 10-cent taffies: 10x cents
• Total cost of 6-cent taffies: 6(x + 10) cents
• Total cost of 8-cent taffies: 8(3x) cents
• Total cost of sugar candies: 2(20) cents

Since the total cost of all the candies is $5.00, we can set up the following equation:

10x + 6(x + 10) + 8(3x) + 2(20) = 500

Solving this equation will give us the values of x and (x + 10), which represent the number of 10-cent taffies and 6-cent taffies Elizabeth bought, respectively.