Question

E is the midpoint of DF . If DE = 6x and EF = x + 10, what is EF?

Answer 1

EF = 12

Explanation:

Given that,

E is the midpoint of DF. So, it can be written as follows :

DE = EF

We have, DE = 6x and EF = x + 10

Putting all the values, we get :

6x = x + 10

taking like terms togther

6x-x = 10

5x = 10

x = 2

Since, EF = x + 10

EF = 2+10 = 12

Hence, the value of EF = 12.