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Find the smallest positive integer divisible by $10$, $11$, and $12$.
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Find the smallest positive integer divisible by $10$, $11$, and $12$.

User Oatmeal
by
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2 Answers

1 vote

Answer:

.

Explanation:

User Jonathon Bolster
by
6.2k points
2 votes

Answer:

Smallest divisible number = 660

Explanation:

Given:

Numbers

10, 11, 12

Find:

Smallest divisible number

Computation:

Factor

10 = 2×5

11 = 11×1

12 = 2×2×3

Smallest divisible number = 2×2×3×5×11

Smallest divisible number = 660

User Curioustechizen
by
6.4k points
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