Question

A car traveling in a straight line has a velocity of 3.29 m/s at some instant. After 4.99 s, its velocity is 8.29 m/s.

What is its average acceleration in this time interval?
Answer in units of m/s^2.

Answer 1

Use the definition of average acceleration:

a = ∆v / ∆t

We have

a = (8.29 m/s - 3.29 m/s) / (4.99 s)

a = 1.002 m/s²