Question

Cisplatin is an antitumor agent. It has the molecular formula Pt(NH3)2Cl2. Show how you can determine the grams of cisplatin that can be produced if the limiting reactant is 1 kg of platinum.

Answer 1

1 kg of Pt produces = 1.56 kg of cisplatin

Step-by-step explanation:

First we find the molecular mass of cisplatin:

M = Molecular Mass of cisplatin = Mol. mass of Pt + 2(Mol. mass of N) + 6(Mol. mass of H) + 2(Mol. mass of Cl)

M = 195 + (2)(14) + (6)(1) + (2)(35.5)

M = 305 a.m.u

Hence,

Mass of 1 mole of cisplatin = 305 g = 0.305 kg

We know that:

1 molecule of Pt produces = 1 mole of cisplatin

Molecular Mass of Pt produces = Mass of 1 mole of cisplatin

195 g of Pt produces = 0.305 kg of cisplatin

0.195 kg of Pt produces = 0.305 kg of cisplatin

1 kg of Pt produces = (0.305/0.195) kg of cisplatin

1 kg of Pt produces = 1.56 kg of cisplatin