Question

A snowmobile has an initial velocity of +3.5

m/s.
If it accelerates at the rate of +0.69 m/s^2
for 8.3 s, what is the final velocity?
Answer in units of m/s.

Answer 1

This follows directly from the definition for average acceleration:

`a_(\rm ave)=(\Delta v)/(\Delta t)=\frac{v_f-v_i}t`

Under constant acceleration, acceleration and average acceleration are interchangeable. So we have

`0.69(\rm m)/(\mathrm s^2)=(v_f-3.5(\rm m)/(\rm s))/(8.3\,\mathrm s)`

`\implies v_f=3.5(\rm m)/(\rm s)+\left(0.69(\rm m)/(\mathrm s^2)\right)(8.3\,\mathrm s)`

`\implies\boxed{v_f=9.227(\rm m)/(\rm s)}`