How many moles are present in 2.60x10^27 atoms of boron (B)?

Question

asked Jul 23, 2021 186k views

1 Answer

Roshna Omer · Answer 1 · 2021-07-27T05:25:35+0000

Answer:

The answer is

Step-by-step explanation:

To find the number of moles of a substance given it's number of entities we use the formula

$n = (N)/(L) \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.60x10^27 atoms of boron

The number of moles is

$n = \frac{2.60 * {10}^(27) }{6.02 * {10}^(23) } \\ = 4318.93687...$

We have the final answer as

Hope this helps you