Question

How many moles are present in 2.60x10^27 atoms of boron (B)?

Answer 1

The answer is

4318.94 moles

Step-by-step explanation:

To find the number of moles of a substance given it's number of entities we use the formula

`n = (N)/(L) \\`

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 2.60x10^27 atoms of boron

The number of moles is

`n = \frac{2.60 * {10}^(27) }{6.02 * {10}^(23) } \\ = 4318.93687...`

We have the final answer as

4318.94 moles

Hope this helps you