Question

If mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", find each measure.

Answer 1

Explanation:

Given mCDF = (3x + 14), mFDE = (5x - 2), and mCDE = (10x – 18)", then the expression mCDE = mCDF+mFDE is true.

To get x, we will substitute the given angles into the formula as shown;

(10x – 18) = (3x + 14)+ (5x - 2)

10x-18 = 3x+5x+14-2

10x-18 = 8x+12

10x-8x = 12+18

2x = 30

x = 30/2

x = 15

Find the measure of each angle

For mCDF:

mCDF = 3x + 14

mCDF = 3(15)+ 14

mCDF = 45+14

mCDF = 59°

For mFDE:

mFDE = (5x - 2)

mFDE = 5(15) - 2

mFDE = 75-2

mFDE = 73°

For mCDE:

mCDE = (10x – 18)

mCDE = 10(15) - 18

mCDE = 150-18

mCDE = 132°