Question

If the order of operation didn’t exist, how many possible solutions can you find for the expression 4+9+16 minus 3 times 5?

Answer 1

Two operations in all

Explanation:

step one:

let us re-write the expression as

4+9+16-3*5

if the order of operation does not count we can perform the operation as

=(4+9+16)-3*5

=(29)-15

=29-15

= 14

step two:

=(4+9+ 13)*5

= 26*5

=130

We can perform two operations in all