We are given with:

Recall the identity what we have for the sine function of complex numbers
Put the values to thus obtain:


Multiply both sides by



Put x =
:

Find the discriminant, here D will be, D = (-2ai)² - 4 × 1 × (-1) = 4 - 4a² = 4(1-a²)
Now, By quadratic formula:




Using the formula for logarithms, we have:


The sine function is periodic on 2πn and zero on (π/2), and the logarithmic expression becomes undefined for all ia±√(1-a²) < 0, so we will take modulus of it
