Question

What is an equation of the line that passes through the points (-2, -5)(−2,−5) and (-1, 1)(−1,1)?

Answer 1

y = 6x + 7

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = )- 2, - 5) and (x₂, y₂ ) = (- 1, 1)

m =
`(1+5)/(-1+2)` = 6 , thus

y = 6x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 1, 1 ) , then

1 = - 6 + c ⇒ c = 1 + 6 = 7

y = 6x + 7 ← equation of line