Question

In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}

3

1

​ of an hour. His swimming partner, Mila, swam \frac {2}{3}

3

2

​ of Logan's distance in \frac {1}{4}

4

1

​ of an hour.

Answer 1

v = 0.625 m/s

Explanation:

Given that,

Total distance is 750 m

Logan swan 750 m in 1/3 hours

His swimming partner, Mila, swam 2/3 of Logan's distance in 1/4 hours.

Note: We need to find Logan's average swimming speed.

Average speed = total distance/total time taken

`v=(750\ m)/((1)/(3)* 3600\ s)\\\\v=0.625\ m/s`

So, Logan's average speed is 0.625 m/s.