Answer:
C₂H₆(g) + 7/2 O₂(g) → 2 CO₂ + 3 H₂O
Step-by-step explanation:
To balance equations of combustion (Chemical + O₂ producing CO₂ and water you must do:
1. Write as CO₂ as carbons in the chemical you have:
For the reaction:
C₂H₆(g) + O₂(g) → CO₂ + H₂O
As you have 2 carbons in ethane:
C₂H₆(g) + O₂(g) → 2 CO₂ + H₂O
2. Write the half of H₂O as hydrogen you have:
There are 6 hydrogens → You must place 3 H₂O:
C₂H₆(g) + O₂(g) → 2 CO₂ + 3 H₂O
3. The last step is to write the half of oxygens you have in products.
4 Oxygens from CO₂ and 3 from water:
C₂H₆(g) + 7/2 O₂(g) → 2 CO₂ + 3 H₂O