Given:
Principal (P)= $1,000
Rate of interest (R)= 4% = 0.04
Simple interest (I)= $100
To find:
The time for which she deposits $1000 into a savings account at 4% simple interest.
Solution:
The formula for simple interest is
![I=P* R* T](https://img.qammunity.org/2021/formulas/mathematics/college/im0q8bw3gnsyb5omf1riifwgh6tvg94q1s.png)
On substituting P=1000, R=0.04 and I=100 in the above formula, we get
![100=1000* 0.04* T](https://img.qammunity.org/2021/formulas/mathematics/high-school/s1ysfpd1zojd7faiv67uhtb1q1zdzw1lix.png)
![100=40T](https://img.qammunity.org/2021/formulas/mathematics/high-school/orn7p87an4ukrirs5aydcbdasr56cdwhp3.png)
Divide both sides by 40.
![(100)/(40)=T](https://img.qammunity.org/2021/formulas/mathematics/high-school/kxp5nqjzx91jo1z15agyywpjc056gkdopl.png)
![2.5=T](https://img.qammunity.org/2021/formulas/mathematics/high-school/d4xuahlewehfxu7ts646au0l49x23udjjk.png)
Therefore, the required time is 2.5 years.