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1. Find the length of AB if A is (3,6) and B is (-3,2) ​

User Politinsa
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4 votes

Answer:

Step-by-step explanation: In isosceles triangle ABC, AB = BC.(2) Bob does his homework if and only if George gets candy.What is the length, to the nearest tenth, of the line segment joining 1.25000. (3) 151.9. (-4-146)2+(2-5272. 6. What is the slope of a line perpendicular to the line whose MLABC = (2x+10), find mLACB. C. rectangular box has a base that is a rectangle with are 10 and 6, find the height of the trapezoid. c) 6. 8) In triangle ABC, the measure of angle A is 60 degrees. If the measure of angle B is 12) Square ABCD, above, has coordinates: C(-2, 2) and D(-2, -2).

Hope this helped!

User Fares
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8.1k points
1 vote

Answer:


\huge{ \boxed{ \tt{2 √(13 )\: \: \sf{units}}}}

Explanation:


\star{ \sf{ \: let \: A(3,6) \: be \: (x1 ,\: y1) \: and \: B(-3,2) \: be \: (x2 \: y2)}}


\sf{Using \: distance ,\: formula \: to \: find \: the \: length \: of \: AB} :


\boxed{ \sf{ \: distance = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) } }}


\mapsto{ \sf{ \sqrt{ {( - 3 - 3)}^(2) + {(2 - 6)}^(2) } }}


\text{Remember!} :

  • The positive integers are always added and posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.


\mapsto{ \sf{ \sqrt{ {( - 6)}^(2) + {( - 4)}^(2) } }}


\mapsto{ \sf{ √(( - 6) * ( - 6) + ( - 4) * ( - 4))}}


\text{Remember!} :

  • Multiplying or dividing positive integers gives a positive integer
  • Multiplying or dividing positive integers by any negative integers gives a negative integer.
  • Multiplying or dividing a negative integer by a positive integer gives a negative integer.
  • Multiplying or dividing a negative integer by a negative integer gives a positive integer.


\mapsto{ \sf{ √(36 + 16)}}


\mapsto{ \sf{ √(52) }}


\mapsto{ \sf{2 √(13) \: units}}


\sf{∴The \: length \: of \: AB \:is \: 2 √(13) \: \: units.}

Hope I helped!

Best regards! :D

~
\sf{TheAnimeGirl}

User Fatih Arslan
by
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