Question

Which is an equation of the line passing through (-2,3) and perpendicular to the line
5x-y=12?

Answer 1

y = -1/5x + 2.6

Explanation:

Put the equation into slope intercept form:

5x - y = 12

-y = -5x + 12

y = 5x - 12

The slope of a perpendicular line will be the opposite reciprocal.

So, the slope of the new line will be -1/5

Then, plug this slope and the given point into the equation y = mx + b to find b

y = mx + b

3 = -1/5(-2) + b

3 = 0.4 + b

2.6 = b

So, the equation will be y = -1/5x + 2.6