Question

A possum is trying to cross the street. Its velocity v as a function of time t is given in the graph below

where rightwards is the positive velocity direction.
v (m/s)
5+
4
3-
2-
1+
4
+
5
t(s)
1
2
3
4
-24
-3+
-4
-5+
What is the possum's displacement Ax from t = 3 s to 5 s?

Answer 1

-10

Step-by-step explanation:

The rectangular area is the base bbb times height hhh.

\begin{aligned}\Delta x&= A \\\\ &=(2\,\text s)\left (-5\,\dfrac{\text m}{\text s}\right ) \\\\ &= -10\,\text m\end{aligned}

Δx

​

=A

=(2s)(−5

s

m

​

)

=−10m

​

The possum displaces 10\,\text m10m10, start text, m, end text to the left.