48.0k views
5 votes
Mark and Don are planning to sell each of their marble collections at a garage sale. If Don has 1 more than 3 times the number of marbles Mark has, how many does each boy have to sell if the total number of marbles is 53?

User Sitaktif
by
8.5k points

1 Answer

0 votes

Answer:

Mark has 13 marbles

Don has 40 marbles

Explanation:

Let the number of Mark's Marbles = M

Let the number of Don's Marble = D

D = 1 + 3M - - - - (1) (Don has 1 more than 3 times the number of marbles Mark has)

D + M = 53 - - - - - (2) (total number of marbles is 53)

puttin the value of D from equation (1) into equation (2)

(1 + 3M) + M = 53

1 + 3M + M = 53

1 + 4M = 53

4M = 53 - 1 = 52

4M = 52

M = 52 ÷ 4

M = 13

finding D by putting the value of M (M = 13) into equation 1

D = 1 + 3M - - - - (1)

D = 1 + 3 (13)

D = 1 + 39

D = 40

∴ Mark has 13 marbles

Don has 40 marbles

User Alex Rudenko
by
8.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories